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This member is one of the top experts of all time, the true elite. Rainner Lins

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I'm a freelance digital applications developer with experience in design, server configuration and maintenance, hands on hardware repair and replacing, mobile application development, SEO and marketing, and a lot of other things that went out of style.

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Country: United States
City: Astoria, NY
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Joined the site: June 29, 2010





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Written in response to It's due to the JSON string being malformed, i also tried it with jQuery 1.7.2 a...:

The { is used for objects with key-pairs, the [ is used for arrays. I didn't see the need to add any arrays in there. the simpler the better when moving data around. Also your JSON string was missing the : and , signs. You can read more about JSON here: http://www.json.org/

The way I formatted it ( used PHP json_encode ) makes it easy to access each user directly like:


var buster = obj.buster.username;


Or, by using a loop as it posted there:


var user = obj[x].username;

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